Added operations_on_set1.py

Author: amratadev

operations_on_set1.py

@@ -0,0 +1,39 @@
+set1={1,2,3,4,5}
+set2={4,10,7,8,-10}
+
+print(set1.isdisjoint(set2))
+print(set1.isdisjoint((6,7,8,9)))#disjoint->both sets items diff from each other
+print(set1.isdisjoint([6,7,8,9]))
+
+#set1 is subset of set2 if every element of set1 is in set2
+print(set1.issubset(set2))
+print(set1.issubset((6,7,8,9)))
+print(set1.issubset([6,7,8,9]))
+
+#set1 is superset of set2 if set1 contains every element of set2
+print(set1.issuperset(set2))
+print(set1.issuperset((6,7,8,9)))
+print(set1.issuperset([6,7,8,9]))
+
+print(set1>=set2)#issuperset like
+
+set3={'Ram','Shyam','Jenny'}
+set4={'Jiya','Aakash'}
+
+print(set3.isdisjoint(set4))
+print(set3.isdisjoint(('Amrata','Priya')))
+print(set3.isdisjoint(['Ram','Shyam']))
+
+print(set3.issubset(['Ram','Shyam','Jenny']))
+print(set3.issubset(set4))
+print(set3.issubset(('Amrata','Priya')))
+
+print(set3.issuperset(['Shyam',]))
+print(set3.issuperset(set4))
+print(set3.issuperset(('Amrata','Priya')))
+
+print(set3 >=set(('Amrata','Priya')))#- Superset check only works between sets.
+print(set1 >=set((6,7,8,9)))
+
+print(set3<=set3)#every element is subset of itself 
+print(set3.issuperset(set3))#every element is superset of itself